In ΔABC, AB=BC=K, AC=√2K, then ΔABC is a:

  1. Right-angled triangle
  2. Isosceles triangle
  3. Right isosceles triangle
  4. Equilateral triangle
Anurag Mishra Professor Asked on 11th December 2015 in Maths.
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  • 1 Answer(s)

    Answer:  (3) Right Isosceles triangle 

    Explanation:-
    In figure – 

    RE: In ΔABC, AB=BC=K, AC=√2K, then ΔABC is a:


    Then, triangle A B C is a Right Isosceles triangle. 

    Hence, the answer is (3) Right triangle. 

    Anurag Mishra Professor Answered on 11th December 2015.
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