# If 10^y=0.0001, 3^4x=81^-1, then the value of 2^-x.16^1/y=

**Answer: (4) 1 **

**Explanation:- **

10^Υ = 0.0001

10^Y = 10^-4

Comparing on both side,

Y = – 4

3^4x = 81^-1

3^4x = 3^-4

Comparing on both side,

4x = – 4

x = – 1

2^-x. 16^1/y

Put the value of x = – 1 & y = – 4

Then, 2^-(-1). 16^1/-4

= 2/2

= 1

Hence, the correct answer is option (4) 1.