If 10^y=0.0001, 3^4x=81^-1, then the value of 2^-x.16^1/y=

 

  1. 2
  2. 3
  3. 10
  4. 1
Anurag Mishra Professor Asked on 29th November 2015 in Maths.
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1 Answer(s)

Answer:  (4) 1 

Explanation:- 
10^Υ = 0.0001
10^Y = 10^-4
Comparing on both side,
Y = – 4

3^4x = 81^-1
3^4x = 3^-4
Comparing on both side,
4x = – 4
x = – 1

2^-x. 16^1/y
Put the value of x = – 1 & y = – 4
Then, 2^-(-1). 16^1/-4
= 2/2
= 1

Hence, the correct answer is option (4) 1.

Anurag Mishra Professor Answered on 1st January 2016.
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