If 10^y=0.0001, 3^4x=81^-1, then the value of 2^-x.16^1/y=

 

  1. 2
  2. 3
  3. 10
  4. 1
Anurag Mishra Professor Asked on 29th November 2015 in Maths.
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  • 1 Answer(s)

    Answer:  (4) 1 

    Explanation:- 
    10^Υ = 0.0001
    10^Y = 10^-4
    Comparing on both side,
    Y = – 4

    3^4x = 81^-1
    3^4x = 3^-4
    Comparing on both side,
    4x = – 4
    x = – 1

    2^-x. 16^1/y
    Put the value of x = – 1 & y = – 4
    Then, 2^-(-1). 16^1/-4
    = 2/2
    = 1

    Hence, the correct answer is option (4) 1.

    Anurag Mishra Professor Answered on 1st January 2016.
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