Find the value of Given Equation ?

If 10y=0.0001, 34x=81-1, then the value of 2-x.161/y=

  1. 2
  2. 3
  3. 10
  4. 1
Anurag Mishra Professor Asked on 26th November 2015 in Maths.
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1 Answer(s)

Answer: (4) 1

Explanation:-
10^y = 0.0001
  = 1/10000
  = 1/10^4 
10^y  = 10 ^- 4
Comparing on both side, 
y  = – 4

3^4x = 81^-1
   = 3^4 x – 1
3^4x  = 3 ^ – 4
Comparing on both side,
4 x = – 4
x = – 1

2^-x . 16^1/y
Put the value of x = -1 & y = – 4
Then, 2^ – (-1) . 16^1/-4
= 2^1 . 16^-1/4
= 2^1. 2^4 x (-1/4)
= 2 . 2^-1
= 2/2
 = 1

Then, the value of 2^-x . 16^1/y is 1.

Hence, the answer is (4) 1. 

Anurag Mishra Professor Answered on 26th November 2015.
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