If (2a-1)²+(4b-3)²+(4c+5)²=0 then the value of (a³+b³+c³-3abc)/(a²+b²+c²) is:

  1. 0
  2. 3 3/8
  3. 2 3/8
  4. 1 3/8
Anurag Mishra Professor Asked on 11th December 2015 in Maths.
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    Answer: (1) 0

    Anurag Mishra Professor Answered on 11th December 2015.
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