In How Much Time Tank will be Filled. If A, B and C are Opened Successively for a Minute Each.

Two pipes A and B can separately fill a tank in 20minutes and 30minutes respectively while a third pipe C can empty it in 15 minutes. If A, B and C are opened successively for a minute each, the tank will be filled in

  1. 60 minutes
  2. 58 minutes
  3. 172 minutes
  4. 180 minutes
Monis Rasool Professor Asked on 10th November 2015 in Maths.
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  • 1 Answer(s)

    Answer is 172 minutes 

    Explanation:-
    Pipe A can fill a tank = 20 minutes 
    Therefore, A can fill a tank in a minute = 1/20

    Pipe B can fill a tank = 30 minutes 
    Therefore, B can fill a tank in a minute = 1/30

    Pipe C can empty it = 15 minutes
    Therefore, C can empty it in a minute = 1/15

    A, B and C are opened = 1/20 + 1/30 – 1/15
     = (3 + 2 – 4)/60
     = 1/60

    1/60 of a tank filled in 3 minutes,
    Therefore,  [1 – (1/20 + 1/30)]
     = 55/60 
    55/60 of a tank filled in 3 x 55 minutes
    Now, 5/60 of the tank  remains to be filled. 
    A will fill 1/20  in 1 minute and B  will fill the remaining 
     = (5/60 – 1/20) 
     = 1/30 in 1 minute
    Therefore, time required = 165 + 1 + 1 + 5
     = 172 minutes

    Hence, the answer is (3) 172 minutes.

    Monis Rasool Professor Answered on 10th November 2015.
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