# A computer producing factory has only two plants T1 and T2

A computer producing factory has only two plants T1 and T2. Plant T1 produces 20% and plant T2 produces 80% of the total computers produced. 7% of computers produced in the factory turn out to be defective. It is known that P(computer turns out to be defective given that is produced in plant T1) = 10P(computer turns out to be defective given that it is produced in plant T2) where P(E) denotes the probability of an event E. A computer produces in the factory is randomly selected and it does not turn out to be defective. Then the probabality that it is produced in plant T2 is

- 36/73
- 47/79
- 78/93
- 75/83