# Then, A Meet B and C at Times: If

A, B and C walk 1 km in 5 min, 8 min and 10 min, respectively. C starts walking from a point, at a certain time, B starts from the same point 1 min later and A starts from the same point 2 min later than C. Then, A meet B and C at times

- 2 min, 3 min
- 4/3 min, 3 min
- 2 min, 5/3 min
- 1 min, 2 min

**Answer: (3) 2 min, 5/3 min Explanation:- **Let the A meets B and C in X & Y min.

The distance covered by A in 5 min = 1 km

Then, the distance covered by A in 1 min = 1000/5 = 200 m.

The distance covered by B in 8 min = 1 km

Then, the distance covered by B in 1 min = 1000/8 = 125 m.

The distance covered by C in 10 min = 1 km

Then, the distance covered by C in 1 min = 1000/10 = 100 m.

According to the question,

Distance covered by C in (X + 2) min = the distance covered by in X min

Then, 100 (X + 2) = 200 X

100 X + 200 = 200 X

200 = 200 X – 100 X

100 X = 200

X = 200/100

X = 2 min.

Now, for A & B

Distance covered by B in (Y + 1) min = Distance covered by A in Y min

Then, 125( Y + 1) = 200 x Y

125 Y + 125 + 200 Y

125 = 200 Y – 125 Y

125 = 75 Y

Y = 125/75

Y = 5/ min.

Hence, the answer is (3) 2 min, 5/3 min.