A passenger train takes 1 hour less for a journey of 120 km :

A passenger train takes 1 hour less for a journey of 120 km, if its speed is increase by 10 km/hour from its usual speed. What is its usual speed?
(A) 50 km/hour
(b) 40 km/hour
(c) 35 km/hour
(d) 30 km/hour

Anurag Mishra Professor Asked on 19th February 2016 in Maths.
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  • 1 Answer(s)

    Answer: (d) 30 km/hour

    Solution:-
    Let the usual speed of a passenger train be X km/hr and time taken by train be Y hr.

    Time taken by train with original speed (Y) = 120/X
    X Y = 120 
    X = 120/Y

    Train 1 hour less for a journey, if its speed is increase by 10 km/hr. 
    Then,  (Y + 10) = 120 /(X – 1)
     (X – 1) (Y + 10) = 120 
    X Y + 10 X – Y – 10 = 120

    Put the value of X = 120/Y, 
    Then,  120 Y/Y + 10 x 120/Y – Y – 10 = 120
    120 + 1200/Y – Y – 10 = 120
    1200  – Y^2  – 10 Y = 0 
    Y^2 + 10 Y – 1200 = 0 
    Y^2 + 40 Y – 30 Y – 1200 = 0 
    Y (Y + 40) – 30 (Y + 40) = 0
    (Y – 30) (Y + 40) = 0 
    Y – 30 = 0 
    Y = 30 

    Then, the usual speed of the train is 30 km/hr. 

    Hence,the correct answer is option (d) 30 km/hr. 

    Anurag Mishra Professor Answered on 19th February 2016.
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