Find the Angle of Projectile of the Horizontal Range :

If the horizontal range of a projectile is four times its maximum height, the angle of projection is

  1. 300
  2. 450
  3. Sin-1(1/4)
  4. Tan-1(1/4)
Manish Listener Asked on 11th October 2015 in Maths.
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1 Answer(s)

Answer: (2) 45o

Explanation:-
The standard equation,

R = u2 sin 2 θ/g
And  h = u2 sin² θ/2g

The horizontal range of projectile is 4 times its maximum height.
Then,  R = 4 h
u2sin2θ/g = 4u2 sin2θ/2g
sin2θ = 2 sin2θ
2 sinθ cosθ = 2 sin2θ                     (sin2θ = 2 sinθ cosθ )
cosθ = sinθ
Sinθ / cos θ = 1
tanθ = tan 45o
θ = 45o
Hence, the answer is (2) 45o

Anurag Mishra Professor Answered on 12th October 2015.
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