Find the Angle of Projectile of the Horizontal Range :

If the horizontal range of a projectile is four times its maximum height, the angle of projection is

  1. 300
  2. 450
  3. Sin-1(1/4)
  4. Tan-1(1/4)
Manish Listener Asked on 11th October 2015 in Maths.
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  • 1 Answer(s)

    Answer: (2) 45o

    Explanation:-
    The standard equation,

    R = u2 sin 2 θ/g
    And  h = u2 sin² θ/2g

    The horizontal range of projectile is 4 times its maximum height.
    Then,  R = 4 h
    u2sin2θ/g = 4u2 sin2θ/2g
    sin2θ = 2 sin2θ
    2 sinθ cosθ = 2 sin2θ                     (sin2θ = 2 sinθ cosθ )
    cosθ = sinθ
    Sinθ / cos θ = 1
    tanθ = tan 45o
    θ = 45o
    Hence, the answer is (2) 45o

    Anurag Mishra Professor Answered on 12th October 2015.
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