# The Area of a Circle Whose Radius is the Diagonal of a Square Whose Area is 4 is:

**Answer: (1) 8 π**

**Explanation:-**

**The area of a square = d²/2**

**Where, d = diagonal of a square.**

Then, 4 = d²/2

d² = 4 x 2

d² = 8

Square root on both side,

d = √8

The radius of a circle = diagonal of a square (Given in the question)

Then,the radius of the circle = √8

**Formula-
The area of the circle = π R² **

**Where, R = radius of the circle.**

Then, the area of the circle = π (√8)²

= 8π

Hence, the answer is (1) 8 π.