Then Area of ΔQBC/Area of ΔPAC is equal to:

ABCD is a square. Draw a triangle QBC on side BC considering BC as base and draw a triangle PAC on AC as its base such that Δ~Δ
Then Area of ΔQBC/Area of ΔPAC is equal to:

  1. 2/1
  2. 1/3
  3. 1/2
  4. 2/3
Anurag Mishra Professor Asked on 10th December 2015 in Maths.
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1 Answer(s)

Answer:  (3) 1/2

Anurag Mishra Professor Answered on 11th December 2015.
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