# Then Area of ΔQBC/Area of ΔPAC is equal to:

ABCD is a square. Draw a triangle QBC on side BC considering BC as base and draw a triangle PAC on AC as its base such that Δ~Δ

Then Area of ΔQBC/Area of ΔPAC is equal to:

- 2/1
- 1/3
- 1/2
- 2/3

ABCD is a square. Draw a triangle QBC on side BC considering BC as base and draw a triangle PAC on AC as its base such that Δ~Δ

Then Area of ΔQBC/Area of ΔPAC is equal to:

- 2/1
- 1/3
- 1/2
- 2/3