Bernoulli’s form of dy/dx (x²y³+xy)+1 is

(a) dy/dx=x2y3-xy
(b) dy/dx-xy=0
(c) dy/dx=x2y3
(d) dy/dx-xy=x2y3

Anurag Mishra Professor Asked on 28th May 2016 in Maths.
Add Comment
  • 0 Answer(s)
  • Your Answer

    By posting your answer, you agree to the privacy policy and terms of service.