The centroid of an equilateral triangle ABC is G and AB=10 cm. The length of AG (in cm) is:

  1. 3 1/3
  2. (10 √3)/3
  3. √3/3
  4. 10/√3
Anurag Mishra Professor Asked on 10th December 2015 in Maths.
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1 Answer(s)

Answer:  (2) 10 sqrt.3/3

Anurag Mishra Professor Answered on 10th December 2015.
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