For the circuit shown, the Norton’s equivalent current source at terminals A & B is given by :

118
(a) 10 ∠0A
(b) 20 ∠0A
(c) 16 ∠86A
(d) 14 ∠36.86A

Anurag Mishra Professor Asked on 1st February 2016 in Physics.
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    Answer: (b) 20 < 0 A 

    Anurag Mishra Professor Answered on 21st May 2016.
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