An elevator descends into a mine-shaft at the rate of 6 m/min :

An elevator descends into a mine-shaft at the rate of 6 m/min. If the elevator starts from 10 m above the ground level the time it will take to reach -350 m is

  1. 45 minutes
  2. 1 hours 30 minutes
  3. 1 hours
  4. 1 hours 15 minutes
Anurag Mishra Professor Asked on 5th December 2015 in Maths.
Add Comment
  • 1 Answer(s)

    Answer: (3) 1 hour

    Explanation:-
    The speed of an elevator = 6 m/min

    The total height covered by the elevator = 10 + 350
     = 360 m

    Then, time taken by the elevator to cover 360 m = 360/6
     = 60 min

    As we know that 1 hr. = 60 min

    Then, the elevator starts from 10 m above the ground level the time it will take to reach – 350 m is 1 hour.

    Hence, the answer is (3) 1 hour.

    Anurag Mishra Professor Answered on 5th December 2015.
    Add Comment
  • Your Answer

    By posting your answer, you agree to the privacy policy and terms of service.