An elevator descends into a mine-shaft at the rate of 6 m/min :

An elevator descends into a mine-shaft at the rate of 6 m/min. If the elevator starts from 10 m above the ground level the time it will take to reach -350 m is

  1. 45 minutes
  2. 1 hours 30 minutes
  3. 1 hours
  4. 1 hours 15 minutes
Anurag Mishra Professor Asked on 5th December 2015 in Maths.
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1 Answer(s)

Answer: (3) 1 hour

Explanation:-
The speed of an elevator = 6 m/min

The total height covered by the elevator = 10 + 350
 = 360 m

Then, time taken by the elevator to cover 360 m = 360/6
 = 60 min

As we know that 1 hr. = 60 min

Then, the elevator starts from 10 m above the ground level the time it will take to reach – 350 m is 1 hour.

Hence, the answer is (3) 1 hour.

Anurag Mishra Professor Answered on 5th December 2015.
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