# Find The Equation of The Line PQ ?

Two straight lines passing through the point *A* (3,2) cut the line 2y=x+3 and *x-*axis perpendicularly at *P and Q* respectively. The equation of the line PQ is

- 7x + y -21 +0
- x + 7y +21 +0
- 2x + y – 8 + 0
- x = 2y +8 = 0