# Find The Difference Of Their Present Age

Two years ago, Rahu was three times as old as his son and two years hence, after two years, twice his age will be equal to five times that of his son. Difference of their present age

- 24 years
- 22 years
- 38 years
- 28 years

**Answer: (1) 24 years**

**Explanation:-**

Let be the age of the Rahu = X years

And the age of his son = Y years

According to the question,

In first condition-

X – 2 = 3 (Y – 2)

X – 2 = 3Y – 6

X – 3 Y = – 6 + 2

X – 3Y = – 4 ………………………. (1)

In second condition-

2 (X + 2) = 5 (Y + 2)

2X + 4 = 5Y + 10

2X – 5Y = 10 – 4

2 X – 5 Y = 6 …………………………… (2)

Solve equation (1) & (2)

Y = 14

Put the value of Y in equation (1)

X – 3 x 14 + – 4

X – 42 = – 4

X = – 4 + 42

X = 38

Thus, the present age of Rahu = 38 years & the present age of his son = 14 years

The difference their age = 38 – 14 = 24 years

Hence, the answer is (1) 24 years.