Find The Difference Of Their Present Age

Two years ago, Rahu was three times as old as his son and two years hence, after two years,  twice his age will be equal to five times that of his son. Difference of their present age

  1. 24 years
  2.  22 years
  3.  38 years
  4.  28 years
Anurag Mishra Professor Asked on 20th July 2015 in Maths.
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1 Answer(s)

Answer: (1) 24 years
Explanation:-
Let be the age of the Rahu = X years
And the age of his son = Y years
According to the question,
In first condition-
X – 2 = 3 (Y – 2)
X – 2 = 3Y – 6
X – 3 Y = – 6 + 2
X – 3Y = – 4                      ……………………….  (1)
In second condition-
2 (X + 2) = 5 (Y + 2)
2X + 4 = 5Y + 10
2X – 5Y = 10 – 4
2 X – 5 Y = 6                  ……………………………  (2)
Solve equation (1) & (2)
Y = 14
Put the value of Y in equation (1)
X – 3 x 14 + – 4
X – 42 = – 4
X = – 4 + 42
X = 38
Thus, the present age of Rahu = 38 years  & the present age of his son = 14 years
The difference their age = 38 – 14 = 24 years
Hence, the answer is (1) 24 years.

Anurag Mishra Professor Answered on 20th July 2015.
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