# Find the Area (in sq.cm) of the Rhombus :

The perimeter of a rhombus is 60 cm and one of its diagonal is 24 cm. The area (in sq.cm) of the rhombus is

- 432
- 206
- 216
- 108

**Answer is (3): 216**

The perimeter of a rhombus = 60 cm (Given)

The perimeter of the rhombus = 4 x side of a rhombus

Then, side of a rhombus = 60/4 = 15 cm

In right angle triangle AOD,

AO = (15^{2} – 12^{2})^{1/2}

AO = (225 – 144)^{1/2}

AO = (81)^{1/2}

AO = 9 cm

Then, diagonal AC = 2 x 9 = 18 cm

**Formula- The area of the rhombus = First diagonal x second diagonal/2**

Then, the area of the rhombus = 18 x 24/2

= 18 x 12

= 216 cm^{2}

Hence, the answer is (3) 216 cm^{2.}