# Find the Sum of Digits of x :

Let x be the least number, which when divided by 5, 6, 7 and 8 leaves a remainder 3 in each case but when divided by 9 leaves no remainder, The sum of digits of x is

- 18
- 21
- 22
- 24

**Answer is (1): 18**

**Explanation:-**Find the LCM of 5, 6, 7 and 8

Factors of 5 = 1 x 5

Factors of 6 = 2 x 3

Factors of 7 = 1 x 7

Factors of 8 = 2 x 2 x 2

Then, the LCM of 5, 6, 7 and 8 = 2 x 2 x 2 3 x 5 x 7

= 840

The second multiple of 840 = 2 x 840

= 1680

Leaves a remainder 3 in each case.

Then, the number = 1680 + 3

= 1683, which is divisible by 5, 6, 7 and 8 leaves a remainder 3 in case each but when divide by 9 leaves no remainder.

Then, the sum of digits of 1683 = 1 + 6 + 8 + 3

= 18

Hence, the answer is (1) 18.