# Find The The Value of (v-e+f) ? If

If the number of vertices, edges and faces of a rectangular parallelepiped are denoted by *v, e* and *f* respectively, the value of (*v-e+f) is:*

- 2
- 0
- 1
- 4

**Answer: (1) 2**

**Explanation:-
**The number of vertices in rectangular parallelogram(v) = 8,

The number of edges rectangular parallelogram(e) = 12,

The number of faces rectangular parallelogram (f) = 6

Then, the value of v – e + f = 8 – 12 + 6

= 14 -12

= 2

Hence, the answer is (1) 2.