# Find The Value of θ in Degrees ? If

If θ be acute angle and tan(4θ-50^{o})=cot(50^{o}-θ), then the value of θ in degrees is:

- 20
- 30
- 40
- 50

**Answer: (2) 30**

**Explanation:-
**tan(4θ-50

^{o})=cot(50

^{o}-θ)

tan (4θ – 50) = tan [90 – (50- θ)]

4θ – 50 = 90 – 50 + θ

4θ =- θ = 40 + 50

3 θ = 90

θ = 90/3

θ =30

Then, the value of θ is 30.

Hence, the answer is (2) 30.