Find the value of x if √(1 + 33/256) = [1 + x/16]

  1. 1
  2. 2
  3. 4
  4. 3
Anurag Mishra Professor Asked on 18th April 2016 in Maths.
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  • 1 Answer(s)

    Answer: (1) 1

    Solution:-
    sqrt.(1 + 33/256) = [1 + X/16]
    Square on both side,
    (1 + 33/256) = [1 + X/16]2
    1 + 33/256 = 1 + (X/16)2 + 2 x 1 x X/16
    33/256 = X2/256 + X/8
    X2/256 + X/8 – 33/256 = 0
    (X2 + 32 X – 33)/256 = 0
    X2 + 32 X – 33 = 0
    X2 + 32 X – 33 = 0
    X2 + 32 X – 33 = 0
    X2 + 33 X – X – 33 = 0
    X (X + 33) – 1 (X + 33) = 0
    (X – 1) (X + 33) = 0
    X – 1 = 0
    X = 1

    Then, the value of X is 1.

    Hence, the correct answer is option (1) 1.

    Anurag Mishra Professor Answered on 23rd April 2016.
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