# Calculate the Average of the Cubes of First Five Natural Numbers?

**All option is wrong**

**Answer: 45**

**Explanation:-
**

**Formula-**

The sum of the cubes of the first n natural numbers = n

^{2}(n + 1)

^{2}/4

Where, n = number of the natural numbers.

Then, the sum of first 5 natural numbers = 5^{2} (5 + 1)^{2}/4

= 5 x 5 x 6 x 6 /4

= 25 x 3 x 3

= 225

Then, the average of the first five natural numbers = 225 / 5

= 45

Hence, the average of the cubes of the first five natural numbers is 45.