If p = cotθ + tanθ and θ = secθ – cosθ :

If p = cotθ + tanθ and θ = secθ – cosθ, then (p2q)2/3 – (q2p)2/3 is equal to
(a) 0
(b) 1
(c) 2
(d) 3

Anurag Mishra Professor Asked on 20th February 2016 in Maths.
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    Answer: (c) 2

    Anurag Mishra Professor Answered on 20th February 2016.
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