In the polynomial ring Z2 [x], 91+x0³=

In the polynomial ring Z2 [x], 91+x0³=
(a) 1+x+x3
(b) 1+x+x2+x3
(c) 1+x2+x3
(d) x+x2+x3

Anurag Mishra Professor Asked on 28th May 2016 in Maths.
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