# What Least Number of Five Digits is Exactly Divisible by 41?

**Answer: (2) 10004**

**Explanation:-**

The least number of five digits = 10000

Then, 10000/41 =243 + 37

Therefore, 10000 + 4 = 10004/41 = 244

Hence, the least number of five digits is 10004 which is exactly divisible by 41.

The answer is (2) 10004.