Find the Least Number in Separately

Find the least number which divide separately by 15, 20, 36 and 48 leaves 3 as remainder in each case

  1. 183
  2. 243
  3. 483
  4. 723
Harsh Vardhan Professor Asked on 14th July 2015 in Maths.
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  • 1 Answer(s)

    Answer: (4) 723
    Explanation:-
    The L C M of 15, 20, 36 and 48.
    Factors of 15 = 3 x 5
    Factors of 20 = 2 x 2 x 5
    Factors of 36 = 2 x 2 x 3 x 3
    Factors of 48 = 2 x 2 x 2 x 2 x 3
    The L C M = 2 x 2 x 2 x 2 x 3 x 3 x 5 = 720
    Remainder = 3
    Then, the least number = 720 + 3 = 723.
    Hence, the answer is (4) 723.

    Anurag Mishra Professor Answered on 14th July 2015.
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