# Find the Least Number in Separately

Find the least number which divide separately by 15, 20, 36 and 48 leaves 3 as remainder in each case

- 183
- 243
- 483
- 723

**Answer: (4) 723**

**Explanation:-**

The L C M of 15, 20, 36 and 48.

Factors of 15 = 3 x 5

Factors of 20 = 2 x 2 x 5

Factors of 36 = 2 x 2 x 3 x 3

Factors of 48 = 2 x 2 x 2 x 2 x 3

The L C M = 2 x 2 x 2 x 2 x 3 x 3 x 5 = 720

Remainder = 3

Then, the least number = 720 + 3 = 723.

Hence, the answer is (4) 723.