Find the Least Number in Separately

Find the least number which divide separately by 15, 20, 36 and 48 leaves 3 as remainder in each case

  1. 183
  2. 243
  3. 483
  4. 723
Harsh Vardhan Professor Asked on 14th July 2015 in Maths.
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1 Answer(s)

Answer: (4) 723
Explanation:-
The L C M of 15, 20, 36 and 48.
Factors of 15 = 3 x 5
Factors of 20 = 2 x 2 x 5
Factors of 36 = 2 x 2 x 3 x 3
Factors of 48 = 2 x 2 x 2 x 2 x 3
The L C M = 2 x 2 x 2 x 2 x 3 x 3 x 5 = 720
Remainder = 3
Then, the least number = 720 + 3 = 723.
Hence, the answer is (4) 723.

Anurag Mishra Professor Answered on 14th July 2015.
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