Find the odd word/letters/number pair from the given alternatives.

Directions: In the following Seven questions, find the odd word/letters/number pair from the given alternatives.

1. (a) Mansion
(b) Lodge
(c) tent
(d) Inn
2. (a)  Sphere
(b) Circle
(c) Square
(d)  Triangle
3. (a) Wing
(b) Fin
(c) Beak
(d) Rudder
4. (a) AKWE
(b) PNTO
(c) LCUF
(d) JHMX
5. (a) 28, 82
(b) 24,44
(c) 99, 99
(d) 36, 63
6. (a) CBUV
(b) YXTU
(c) RQOP
(d0 IJSO
7. (a) 84, 67
(b) 112, 95
(c) 79, 63
(d) 167, 150
Anurag Mishra Professor Asked on 8th February 2016 in
1. (c) tent

Explanation:-
Tent is an odd word in  the all given words.

Hence, the correct answer is option (c) tent.

2. (a) sphere

Explanation:-
Sphere is a three dimension figure but rest two dimension figure.

Hence, the correct answer is option (a) sphere.

3. (d) Rudder

Explanation:-
Rubber is an odd but rest are the body parts of a bbird.

Hence, the correct answer is option (d) Rubber.

4. (d) JHMX

Explanation:-
The group of letters “JHMX” has no any vowels but rest are have a vowels.

Hence, the correct answer is option (d) JHMX.

5. (b) 24, 44

Explanation:-
The digit of option (b)’s is not reverse but rest are all options’s numbers are reversed.

Hence, the correct answer is option (b) 24, 44.

6. (d) IJSO

Explanation:-
C – 1 = B  &  U + 1 = V,
Y – 1 = X  &  T + 1 = U,
R – 1 = Q  &  O + 1 = P,
I + 1 = J  & S – 3 = O.

Then, the odd option is (d) IJSO.

Hence, the correct answer is option (d) IJSO.

7. (c) 79, 63

Explanation:-
8  + 4 = 12  &  6 + 7 = 13,
11 + 2 = 13  &  9 + 5 = 14,
7 + 9 = 16  &  6 + 9 = 15,
1 + 6 + 7 = 14 &  15 + 0 = 15.

Then, the odd numbers are 79, 63.

Hence, the correct answer is option (c) 79, 63.

Anurag Mishra Professor Answered on 8th February 2016.