The sum of the Natural Numbers which are Divisors of -100 is

  • 116
  • 117
  • 216
  • 217
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    The sum of the natural numbers which are Divisors of 100 is 217.

    Formula

     

    (Pa) = (Pa + 1 – 1) / (P – 1)

    Where, P = Divisors and a = power of prime number.

    s(100) = s(22 x 55). As 22 and 55 are relatively prime,

    s(22) = 23 – 1 = 7 and s(55) = (53 – 1) / 4 = 31.

    Therefore, s(100) = 7 x 31 = 217. Ans.

    (Pa) = (Pa + 1 – 1) / (P – 1)

    Where, P = Divisors and a = power of prime number.

    s(100) = s(22 x 55). As 22 and 55 are relatively prime,

    s(22) = 23 – 1 = 7 and s(55) = (53 – 1) / 4 = 31.

    Therefore, s(100) = 7 x 31 = 217. Ans.

    Anurag Mishra Professor Answered on 10th May 2015.
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