If number 62532915a is completely divisible by 6 :

If number 62532915a  is completely divisible by 6, then the largest digit at the place of ‘a’ will be

  1. 5
  2.  6
  3.  8
  4.  9
Anurag Mishra Professor Asked on 5th December 2015 in Maths.
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  • 1 Answer(s)

    Answer: (2) 6

    Divisibility of 6 =>  If the number of 6 divisible 2 and 3 that number divisible by 6.
    Divisibility of 2 =>If the unit digit of the number if zero or even number that number divisible by 2.
    Divisibility of 3 => If the sum of the digit of the number is divisible by 3 that number divisible by 3.

    Then, the sum of the digit of the number 62532915 a = 6 + 2 + 5 + 3 + 2 + 9 + 1 + 5 + a
     = 33 + a
    If we put  a = 6 which is a even number,the number surely divisible by 2.
    And sum = 33 + 6 = 39  which is divisible 3.

    Then, the largest digit at the place of ‘a’ will be 6.

    Hence, the answer is (2) 6.  

    Anurag Mishra Professor Answered on 5th December 2015.
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