The numerical value of  (9/cosec²θ)+ 4cos²θ+(5/1+tan²θ):

  1. 9
  2. 4
  3. 5
  4. 7
Monis Rasool Professor Asked on 21st November 2015 in Maths.
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  • 1 Answer(s)

    Answer: (1) 9

    Explanation:-
    9/cosec²θ + 4 cos²θ + 5/(1 + tan²θ)
    9 sin²θ + 4 cos²θ + 5/sec²θ                                (sin²θ = 1/cosec²θ  & 1 + tan²θ = sec²θ)
    5 sin²θ + 4 sin²θ + 4 cos²θ + 5 cos²θ                       (cos²θ  = 1/sec²θ)
    5 sin²θ + 5 cos²θ + 4 sin²θ + 4 cos²θ
    5 (sin²θ + cos²θ) + 4 (sin²θ + cos²θ)
    5 (1) + 4 (1)                                                                      (sin²θ + cos²θ = 1)
    = 5 + 4
    = 9

    Hence, the answer is (1) 9.

    Anurag Mishra Professor Answered on 21st November 2015.
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