# How Many Percent Increased in The Surface Area of Cube ? If

Answered

The percentage increase in the surface area of a cube when each side is doubled is:

- 150%
- 50%
- 200%
- 300%

Best answer

**Answer: (4) 300%**

**Explanation:-**

Let the side of a cube be X

**Formula-**

**The surface of the cube = 6 a ^{2}**

**Where, a = side of the cube.**

Then, The surface area of the cube = 6 X^{2}

If the each side is doubled,

Then, the surface area of the cube = 6 (2 X)^{2}

= 6 x 4 X^{2}

= 24 X^{2}

Increased surface area = 24 X^{2} – 6 X^{2}

= 18 X^{2}

Increase surface area in percent = 18 X^{2} x 100/6 X^{2}

= 300 %

Then, The percentage increase in the surface area of a cube when each side is doubled is 300 %.

Hence, the answer is (4) 300%.