How Many Percent Increased in The Surface Area of Cube ? If
Answer: (4) 300%
Let the side of a cube be X
The surface of the cube = 6 a2
Where, a = side of the cube.
Then, The surface area of the cube = 6 X2
If the each side is doubled,
Then, the surface area of the cube = 6 (2 X)2
= 6 x 4 X2
= 24 X2
Increased surface area = 24 X2 – 6 X2
= 18 X2
Increase surface area in percent = 18 X2 x 100/6 X2
= 300 %
Then, The percentage increase in the surface area of a cube when each side is doubled is 300 %.
Hence, the answer is (4) 300%.