# What will be the Percentage of Water in the New Mixtures? If

Three vessels whose capacities are 3:2:1 are completely filled with milk mixed with water. The ratio of milk and water in the mixture of vessels are 5:2, 4:1 and 4:1 respectively. Taking 1/3^{rd} of first 1/2 of second and 1/7^{th} of third mixture, a new mixture kept in a new vessel is prepared. The percentage of water in the new mixtures is:

- 28
- 24
- 32
- 30

**Answer: (2) 24%**

**Explanation:-**

Let be the capacity of three mixture = 3X, 2X and X

1/3 of first vessels = 3X/3 = X

1/2 of second vessels = 2X/2 = X

1/7 of third mixture = X/7

The quantity of new mixture = X + X + X/7

= (7X + 7X + X )/7

= 15X/7

The percentage of water = 2X/7 + X/5 + X/5×7

= (10X + 7X + X)/35

= 18X/35

The percentage of water = 18X x 7 x 100/35 x 15

= 24%

Hence, the answer is (2) 24%.