# What are the population of the town two years before and after one year

The population of a decrease at the rate of 4% per annum. If its present population is 57600, then the difference in the town two years before and after one year from now will be

- 6820
- 4608
- 7004
- 7204

**Answer: (3) 7004**

**Solution:-**

The present population of the town = 57600

If the population of a town decreased at rate of 4% per annum.

The population of a town two years before = 57600 (1 + 4/100)^2

= 57600 x 26 x 26/25 x 25

= 62300.16

The population of a town after two years = 57600 (1 – 4/100)^2

= 57600 x 24/25

= 55296

The difference of population of a town in two years before and two years after = 62300 – 55296

= 7004

Hence, the correct answer is option (3) 7004.