The smallest five digit number which is divisible by 12,18 and 21 is:

  1. 10080
  2. 50321
  3. 30256
  4. 10224
Anurag Mishra Professor Asked on 11th December 2015 in Maths.
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  • 1 Answer(s)

    Answer: (1) 10080

    Explanation:-

    The factors of 12 = 2 x 2 x 3
    The factors of 18 = 2 x 3 x 3 
    The factors of 21 = 3 x 7

    Then, the L C M of 12, 18,  21 = 2 x 2 x 3 x 3 x 7 
     = 252

    The smallest number of five digits = 10000
    Then, 10000/252
     = 39 and remainder 172
    172 + 80 = 252

    Then, the smallest number of five digits = 10000 + 80
     = 10080

    Hence, the answer is (1) 10080. 

    Anurag Mishra Professor Answered on 11th December 2015.
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