Solution of 3e×/1-e×dx+sec²y/tan y dy=0 is

(a) tan y=C(1-ex)3
(b) tan y =C(1-ex)
(c) tan y= C(1-ex)2
(d) none

Anurag Mishra Professor Asked on 28th May 2016 in Maths.
Add Comment
  • 0 Answer(s)
  • Your Answer

    By posting your answer, you agree to the privacy policy and terms of service.