The Total Surface area of a Regular Triangular Pyramid with Each Edges of Length 1 cm is:

  1. sqrt. 3 sq. cm
  2. (4/3) sqrt. 3
  3. 4 sq. cm
  4. 4 sqrt. 3 sq. cm
Monis Rasool Professor Asked on 8th July 2015 in Maths.
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    Answer : (1). sqrt. 3 sq. cm

    RE: The Total Surface area of a Regular Triangular Pyramid with Each Edges of Length 1 cm is:

    In the above figure , we see that a regular triangular pyramid is made up of four equilateral triangles.
    the equilateral triangle having each side  = 1cm
    so, total surface area of the above pyramid = 4 * area of one equilateral triangle.
    Total surface area of pyramid = 4 * 1 * sqrt.(3) / 4
    Total surface area of pyramid = sqrt.(3) * 4 / 4
    Total surface area of pyramid = sqrt.(3) sq. cm

    vijay Professor Answered on 14th July 2015.
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