# If tanθ+secθ+3, θ being acute, the value of 5 sinθ is:

**Answer: (2) 4**

**Explanation:-
**tanθ + secθ = 3

sinθ/cosθ + 1/cosθ = 3

(sinθ + 1)/cosθ = 3

sinθ + 1 = 3 cosθ

Sinθ = 3 cosθ – 1

**Answer: (2) 4**

**Explanation:-
**tanθ + secθ = 3

sinθ/cosθ + 1/cosθ = 3

(sinθ + 1)/cosθ = 3

sinθ + 1 = 3 cosθ

Sinθ = 3 cosθ – 1