If ∝+β=90º then the expression :

(tan∝/tanβ) +sin²∝ +sin2β is equal to

  1. sec2
  2. sec2β
  3. tan2β
  4. tan2
Anurag Mishra Professor Asked on 11th December 2015 in Maths.
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1 Answer(s)

Answer: (1) sec²∝

Explanation:-
∝+β=90º              (Given)
β = 90º – ∝

tan∝/tanβ + sin²∝  + cos²β
= tan∝/tan(90º – ∝)  +  sin²∝  + cos²(90º – ∝)
= tan∝/cot∝ + sin²∝  + cos²∝
As we know that sin²∝  + cos²∝ = 1 and tan∝ = 1/cot∝

Then, tan²∝ + 1
= sec²∝

Hence ,the answer is (1) sec²∝.

Anurag Mishra Professor Answered on 11th December 2015.
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