# Find The Angle RQP = ?

In a circle if PQ is the diameter of the circle and R is on the circumference of the circle such that angle PQR = 30^{0} then angle RPQ =

- 90
^{0}

- 60
^{0}

- 30
^{0}

- 45
^{0}

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**Answer: (2). 60 degree.**

The diameter of the circle is PQ.

R is a point on the circumference of the circle.

Angle PQR = 30^{o }(given)

As we know that angle sustained on the circumference of circle is 90^{0}

On joining points P, Q, R It forms a Triangle PQR.

In Triangle PQR,

Angle (RPQ) + Angle (PQR) + Angle (PRQ) = 180^{0 }(Angle sum property of triangle)

Angle (RPQ) + 30^{0} + 90^{0 }= 180^{0}

Angle (RPQ) = 180^{0 }– 120^{0}

Angle (RPQ) = 60^{0}