The LCM of two numbers is 2310 and their HCF is 30. If one of the number is 7×30, find the other number.

(a) 220
(b) 330
(c) 425
(d) 512

Anurag Mishra Professor Asked on 16th May 2016 in Maths.
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  • 1 Answer(s)

    Answer: (b) 330 

    Solution:-
    The LCM of two numbers = 2310 
    The HCF of two numbers = 30 
    One of the number = 7 x 30 

    Formula- 
    The product of two numbers = the product of HCF ans LCM. 

    Then, 
    2310 x 30 = 7 x 30 x other number 
    other number = 2310/7
     = 330 

    So, the other number will be 330. 

    Hence, the correct answer is option (b) 330. 

    Anurag Mishra Professor Answered on 18th May 2016.
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