# The LCM of two numbers is 2310 and their HCF is 30. If one of the number is 7×30, find the other number.

(a) 220

(b) 330

(c) 425

(d) 512

**Answer: (b) 330 **

**Solution:-**

The LCM of two numbers = 2310

The HCF of two numbers = 30

One of the number = 7 x 30

**Formula- **

**The product of two numbers = the product of HCF ans LCM.**

Then,

2310 x 30 = 7 x 30 x other number

other number = 2310/7

= 330

So, the other number will be 330.

Hence, the correct answer is option (b) 330.