The LCM of two numbers is 2310 and their HCF is 30. If one of the number is 7×30, find the other number.
Answer: (b) 330
The LCM of two numbers = 2310
The HCF of two numbers = 30
One of the number = 7 x 30
The product of two numbers = the product of HCF ans LCM.
2310 x 30 = 7 x 30 x other number
other number = 2310/7
So, the other number will be 330.
Hence, the correct answer is option (b) 330.