Find The Value of The Following Term ?

The value of sin222o + sin268o + cot230o is:

  1. 5/4
  2. 4
  3. 3/ 4
  4. 3
Anurag Mishra Professor Asked on 22nd August 2015 in Maths.
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  • 1 Answer(s)

    Answer: (2) 4

    Explanation:-

    Sin2220 + sin2680 + cot2300
    = sin2220 + sin2 (90 – 22)o + cot230o
    = sin222o + cos222o + cot230o              [sin(90 – A) = cos A]
    = 1 + cot230o                                       [sin2A + cos2A = 1]
    = 1 + (sqrt.3)2                                       (cot30o = sqrt.3)
    = 1 + 3
    = 4

    Hence, the answer is (2) 4.

     

    Anurag Mishra Professor Answered on 22nd August 2015.
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