# When divided by 30, 36, & 80 gives a remainder 11 in each case is :

A number between 1000 and 2000 which when divided by 30, 36, & 80 gives a remainder 11 in each case is

- 1641
- 1712
- 1523
- 1451

**Answer is 1451**

**Explanation:-**

The factors of 30 = 2 x 3 x 5

The factors of 36 = 2 x 2 x 3 x 3

The factors of 80 = 2 x 2 x 2 x 2 x 5

Then, the L C M of 30, 36, 80 = 2 x 2 x 2 x 2 x 3 x 3 x 5

= 720

The second multiple of 720 = 720 x 2 = 1440 which is between 1, 000 and 2, 000.

Gives remainder = 11

Then, the number = 1440 + 11

= 1451

Then, a number between 1, 000 and 2, 000 which when divided by 30, 36 & 80 gives a remainder 11 in each case is 1451.

Hence, the correct answer is option (4) 1451.