# Find the Value of tan (θ+15º)/tan (θ-15º) :

If tanθ -cotθ=0 and θ is positive acute angle, then the value of tan (θ+15º)/tan (θ-15º) is

- √3
- 1/3
- 1/√3
- 3

**Answer is (4): 3
**

**Explanation:-**

tanθ – cotθ = 0

Taken, θ = 45°

Then, tan45° – cot45° = 0

1 – 1 = 0

Then, the θ = 45°

Put the value of θ = 45°

Then, tan (45 + 15)/tan (45- 15)

= tan60°/tan30°

= √3/(1/√3)

= √3 x √3

= 3

Hence, the answer is (4) 3.