Find the Value of tan (θ+15º)/tan (θ-15º) :

If tanθ -cotθ=0 and θ is positive acute angle, then the value of tan (θ+15º)/tan (θ-15º) is

  1. √3
  2. 1/3
  3. 1/√3
  4. 3
Anurag Mishra Professor Asked on 26th October 2015 in Maths.
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1 Answer(s)

Answer is (4): 3

Explanation:-

tanθ – cotθ = 0
Taken, θ = 45°
Then, tan45° – cot45° = 0
1 – 1 = 0
Then, the θ = 45°

Put the value of θ = 45°
Then, tan (45 + 15)/tan (45- 15)
= tan60°/tan30°
= √3/(1/√3)
= √3 x √3
= 3

Hence, the answer is (4) 3.

Monis Rasool Professor Answered on 28th October 2015.
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