If x=a secθ +b tan θ and y= a tan θ + b sec θ (a≠b) :

If x=a secθ +b tan θ and y= a tan θ + b sec θ (a≠b), then the value of (x²-y²)/a²-b²) is

  1. 1
  2. 1/2
  3. 0
  4. 2
Anurag Mishra Professor Asked on 7th November 2015 in Maths.
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1 Answer(s)

Answer:  (1) 1

Anurag Mishra Professor Answered on 17th November 2015.
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