If x=a secθ +b tan θ and y= a tan θ + b sec θ (a≠b) :

If x=a secθ +b tan θ and y= a tan θ + b sec θ (a≠b), then the value of (x²-y²)/a²-b²) is

  1. 1
  2. 1/2
  3. 0
  4. 2
Anurag Mishra Professor Asked on 7th November 2015 in Maths.
Add Comment
  • 1 Answer(s)

    Answer:  (1) 1

    Anurag Mishra Professor Answered on 17th November 2015.
    Add Comment
  • Your Answer

    By posting your answer, you agree to the privacy policy and terms of service.