# What will be the Value of (X+Y)/X2? If

The sum of two positive numbers is 20% of the sum of their squares and 25% of the difference of their squares. If the numbers are X and Y then

__X + Y__ is equal to-

X^{2}

- 1/3
- 3/8
- 2/9
- 1/4

**Answer: (3) 2/9**

**Explanation:-
**The sum of two positive numbers is 20% of their squares,

Then, X + Y = (X

^{2}+ Y

^{2}) x 20/100

X + Y = (X

^{2}+ Y

^{2})/5

X

^{2}+ Y

^{2}= 5 (X + Y) ………………………….. (1)

And 25% of the difference of their squares,

Then, X + Y = (X^{2} – Y^{2}) x 25/100

X + Y = (X^{2} – Y^{2})/4

X^{2} – Y^{2} = 4 (X + Y) ………………………………. (2)

Add equation (1) & (2),

X^{2} + Y^{2} + X^{2} – Y^{2} = 5X + 5Y + 4X + 4Y

2X^{2} = 9 X + 9 Y

2X^{2} = 9 (X + Y)

(X + Y)/X^{2} = 9/2

Then, the value of (X + Y)/X^{2} = 9/2

Hence, the answer is (3) 2/9.

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