# Which term of the AP 3, 15, 27, 39………. will be 132 more than its 54th term?

**Answer: (4) 65 **

**Solution:-**

First term (a) = 3,

d = 15 – 3

= 12

**Formula-**nth term = a + (n – 1) d

Then, 54th term = 3 + (54 – 1) 12

= 3 + 53 x 12

= 639

Then, the value of nth term which is 132 more than 54th term .

Then, nth term = 639 + 132

nth term = 771

3 + (n – 1) 12 = 771

(n – 1) 12 = 771 – 3

n – 1 = 768/12

n – 1 = 64

n = 64 + 1

n = 65

Hence, the correct answer is option (4) 65.