# If the liquid X costs Rs.2 more per liter then Y, the cost of X per liter is (in Rs.):

The liquids, X and Y are mixed in the ratio of 3:2 and the mixture is sold at Rs.11 per liter at a profit of 10%. If the liquid X costs Rs.2 more per liter then Y, the cost of X per liter is (in Rs.):

- 9.50
- 10.80
- 11.75
- 11

**Answer: (2) 10.80**

**Explanation:-**

The ratio of liquids X and Y in the mixture = 3: 2

Let the quantity of liquid X be 3 A & quantity of Y be 2 A

Again, let total cost price of the mixture be Rs.100

Profit = 10%

Then selling price of mixture (3 A + 2 A) x 11 = 110

5 A = 10

A = 2

Then quantity of liquid X = 3 X = 3 x 2 = 6 liters and quantity of liquid Y = 2 X = 2 x 2 = 4 liters

Total quantity of mixture = 6 + 4 = 10 liters

Let the cost price of liquid Y be Rs. B per liter

Then cost price of liquid X will be (B + 2) per liter

6 (B + 2 ) + 4 B = 100

6 B + 12 + 4 B = 100

10 B + 12 = 100

10 B = 100 – 12

10 B = 88

B = 8.8

Then price of liquid Y = B = Rs.8.8 and price of liquid X = 8.8 + 2

= Rs.10.8

Hence, the correct answer is option (2) 10.80